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0.5x^2-x-7=0
We add all the numbers together, and all the variables
0.5x^2-1x-7=0
a = 0.5; b = -1; c = -7;
Δ = b2-4ac
Δ = -12-4·0.5·(-7)
Δ = 15
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{15}}{2*0.5}=\frac{1-\sqrt{15}}{1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{15}}{2*0.5}=\frac{1+\sqrt{15}}{1} $
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